strtok behaviour when uninitialized
Ondřej Bílka
neleai@seznam.cz
Mon Feb 19 18:37:00 GMT 2018
On Mon, Feb 19, 2018 at 06:41:20PM +0100, Andreas Schwab wrote:
> On Feb 19 2018, OndÅej BÃlka <neleai@seznam.cz> wrote:
>
> > It is function that's broken by design, even without threads. If one
> > calls any library function while strtok is going and then in later
> > version of library one decides to also use strtok it will break previous
> > one.
>
> All standard library functions are required to behave as if they never
> call strtok.
>
I was talking about third party libraries.
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