strtok behaviour when uninitialized

[Andreas Schwab]

On Feb 19 2018, Ondřej Bílka <neleai@seznam.cz> wrote:

> It is function that's broken by design, even without threads. If one
> calls any library function while strtok is going and then in later
> version of library one decides to also use strtok it will break previous
> one.

All standard library functions are required to behave as if they never
call strtok.

Andreas.

-- 
Andreas Schwab, SUSE Labs, schwab@suse.de
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