Should nanl(0) crash?

[Robert Love]

On Sat, 2004-07-24 at 23:02 +0200, Petter Reinholdtsen wrote:

> This code compile, run and print 0 on Tru64 Unix.  On Linux, it
> crashes with a segfault.  Is it legal to call nanl(0)?  I tried
> checking the C standard, but that didn't make me wiser. :(

While it probably makes sense for nanl(0) not to crash, the argument's
behavior is "unspecified" so this is probably within the realm of
standards conformance.

	Robert Love