Should nanl(0) crash?

Petter Reinholdtsen pere@hungry.com
Sat Jul 24 21:38:00 GMT 2004


This code compile, run and print 0 on Tru64 Unix.  On Linux, it
crashes with a segfault.  Is it legal to call nanl(0)?  I tried
checking the C standard, but that didn't make me wiser. :(

#include <math.h>
#include <stdio.h>
int main() {
  long double a = nanl(0);
  printf("%Lf\n", a);
  return 0;
}



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