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Re: [PATCH 1/2] gdb: Convert completion tracker to use std types
- From: Tom Tromey <tom at tromey dot com>
- To: Andrew Burgess <andrew dot burgess at embecosm dot com>
- Cc: gdb-patches at sourceware dot org
- Date: Fri, 24 Jan 2020 11:54:03 -0700
- Subject: Re: [PATCH 1/2] gdb: Convert completion tracker to use std types
- References: <cover.1577481992.git.andrew.burgess@embecosm.com> <c9cf5478c7c3d4fc0af6f484d8acd007fd7bb8b2.1577481993.git.andrew.burgess@embecosm.com>
>>>>> "Andrew" == Andrew Burgess <andrew.burgess@embecosm.com> writes:
Andrew> For now then I'm holding the raw 'char *' within the unordered_map,
Andrew> and rely on the completion_tracker object to delete the data if
Andrew> needed, or to ensure that the data is passed over to readline, which
Andrew> will do the deletion for us.
Seems reasonable enough.
Andrew> + for (const auto &p : m_entries_hash)
Andrew> + {
Andrew> + xfree ((char *) p.first);
Andrew> + xfree ((char *) p.second);
Maybe const_cast would be better?
Andrew> + /* A map of completions. The key is the completion, and the value is the
Andrew> + string to be used to compute the lowest common denominator. Both the
Andrew> + key and the value are owned by the completion_tracker class while
Andrew> + being held in this map, as such completion_tracker must free these
Andrew> + strings when finished with them, or pass ownership to someone else who
Andrew> + will free them. */
Andrew> + typedef std::unordered_map<const char *, const char *, std::hash<std::string>,
Andrew> + std::equal_to<std::string>> completion_set;
Does using std::string here mean that a temporary std::string will be
made for each insertion in the map? And also for comparisons?
That seems expensive if so.
Tom