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On Thu, Oct 15, 2009 at 6:00 PM, H.J. Lu <hjl.tools@gmail.com> wrote: > 2009/10/15 Adam Nemet <anemet@caviumnetworks.com>: >> "H.J. Lu" <hjl.tools@gmail.com> writes: >>> On Thu, Oct 15, 2009 at 4:46 PM, David Daney <ddaney@caviumnetworks.com> wrote: >>>> H.J. Lu wrote: >>>>> >>>>> I am checking in this patch to use enum instead of nested macros. >>>> >>>> [...] >>>>> >>>>> +enum >>>>> +{ >>>>> + ?REG_80 = 0, >>>>> + ?REG_81 = REG_80 + 1, >>>>> + ?REG_82 = REG_81 + 1, >>>> >>>> Am I missing something, or is every single one of your ' = foo + 1' in this >>>> patch completely redundant? >>> >>> Do all compiler guarantee that bar == 1 with >>> >>> enum >>> { >>> ? foo = 0, >>> ? bar >>> }; >>> >>> If yes, I'd love to get rid of "foo + 1". >> >> Yes. ?6.7.2.2#3: >> >> ?The identifiers in an enumerator list are declared as constants that >> ?have type int and may appear wherever such are permitted.107) An >> ?enumerator with = defines its enumeration constant as the value of the >> ?constant expression. If the first enumerator has no =, the value of >> ?its enumeration constant is 0. Each subsequent enumerator with no = >> ?defines its enumeration constant as the value of the constant >> ?expression obtained by adding 1 to the value of the previous >> ?enumeration constant. (The use of enumerators with = may produce >> ?enumeration constants with values that duplicate other values in the >> ?same enumeration.) The enumerators of an enumeration are also known as >> ?its members. >> > > Great. I will make the change. > This is the patch I checked in. Thanks. -- H.J.
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