This function works incorrectly in case when argument is of
long double type and precision is set to zero.
For example, call
   printf( "%.0LA", ( long double ) 0x0.FFFFp+0 );
will output string "0XP+8" with character number 1 missing
between "X" and "P" instead of "0X1P+0".

------- Additional Comment #1 From Ulrich Drepper 2006-08-03 09:24 -------

Actually, the output contains something between X and P.  It's '\1', not '1'. 
That's fixed now.