Created attachment 6850 [details]
Source for test case

Given the attached gdb-test.cpp file compiled as follows:
 $ g++ -O2 -g gdb-test.cpp -o gdb-test

This program has a structure named fibs and a global variable also named fibs.  When you use gdb (as follows) you cannot get to the value of the global variable because GDB seems to only see the typename:

 $ gdb ./gdb-test

 (gdb) start
 ...
 (gdb) print fibs
 Attempt to use a typename as an expression

(This is the instance of that error from gdb/expr.c)

The .debug_info section seems to be correct (objdump --dwarf=info output also attached).