memset (0, 0, 0);
Fri Apr 4 15:04:00 GMT 2003
On Fri, Apr 04, 2003 at 03:52:32PM +0100, Joern Rennecke wrote:
> On some processors, memset can be implemented more efficiently
> when you always read - and possibly also write back - the first
> memory word contained partially or in whole in the to-be-modified
> This conflicts with gdb usage of memset (0, 0, 0); in some places.
> There are three practical questions here:
> - should gdb use this idiom?
> - should all target-specific variants of newlib's memset implement it?
> - should all target-specific variants of glibc's memset implement it?
Where is it that GDB does this?
MontaVista Software Debian GNU/Linux Developer
More information about the Newlib