librt and libpthread in alternate prefix

[Poor Yorick]

Mike Frysinger wrote:
 > On Thursday 14 May 2009 21:06:49 Poor Yorick wrote:
 >> Mike Frysinger wrote:
 >>  > On Thursday 14 May 2009 20:00:36 Poor Yorick wrote:
 >>  >> Mike Frysinger wrote:
 >>  >>  > On Tuesday 12 May 2009 10:15:16 Poor Yorick wrote:
 >>  >>  >> Mike Frysinger wrote:
 >>  >>  >>  > On Monday 11 May 2009 23:34:16 Poor Yorick wrote:
 >>  >>  >>  >> Because my goal is to build a software collection in an
 >>  >>  >>  >> alternate library path which uses its own glibc, I'm trying to
 >>  >>  >>  >> get the new loader to work from the alternate location without
 >>  >>  >>  >> setting --library-path.
 >>  >>  >>  >
 >>  >>  >>  > so use a wrapper script that builds paths using $0
 >>  >>  >>
 >>  >>  >> That's a kludge that doesn't work well, since wrapper scripts
 >>  >>  >> aren't suitable for the #! line.
 >>  >>  >
 >>  >>  > i dont really know what you're talking about here.  #!/bin/sh works
 >>  >>  > just fine.
 >>  >>
 >>  >> I mean that I can't wrap binaries compiled against the alternate glibc
 >>  >> in a script that calls the real binary using the new loader.  For
 >>  >> example, if I wrap awk in a script called awk_new, I can't do this:
 >>  >>
 >>  >> 	!# /path/to/alternate/awk_new
 >>  >>
 >>  >> because the !# mechanism requires a binary, not a script.
 >>  >
 >>  > your wrapper is a script that executes the right ldso with the right
 >>  > paths. use #!/bin/sh like normal.
 >>
 >> If this is what you had in mind (awk being a wrapper for the real awk):
 >>
 >>      #! /bin/sh /path/to/alternate/bin/awk
 >
 > i dont know why you keeping going down this line of logic.  you said you're
 > concerned with running different libs and that's it.
 > #!/bin/sh
 > ${0%/*}/ld.so .....
 > -mike

This is not acceptable, because if this script is called "awk", users will
expect to be able to do this:

     #! /path/to/alternate/bin/awk

and they will get a "permission denied" error, because now awk is just a script
(wrapping the real awk) instead of an executable.  On the #! line, the second
item must be binary executable, not a script.

-- 
Yorick