glibc 2.21 - Machine maintainers, please test your machines.

[Andreas Schwab]

Torvald Riegel <triegel@redhat.com> writes:

> I don't think so, because in a badly 4B-aligned (ie, no 8B-aligned) use,
> struct new_sem is at offset 4 of the semaphore.  If you copy that to a
> 8B-aligned semaphore just bit-by-bit, then the actual data will still
> start at offset 4, but to_new_sem will assume offset 0.

It is undefined to use a copy of a sem_t in any of the semaphore calls.

Andreas.

-- 
Andreas Schwab, schwab@linux-m68k.org
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