[PATCH] Call memcpy in generic mempcpy
Roland McGrath
roland@hack.frob.com
Wed Feb 6 23:19:00 GMT 2013
> On 02/06/13 12:53, Ond$,1 y(Bej B,Am(Blka wrote:
> > unsigned long int dstp = (long int) dstpp;
> ...
> > + memcpy (dstpp, srcpp, len);
> > + return (void *) (dstp + len);
>
> There's no need to use an integer type, or
> to do any casts. Something like this, perhaps?
>
> char *dstp = dstpp;
> memcpy (destpp, srcpp, len);
> return dstp + len;
It's GNU code and can assume GNU C extensions.
So there isn't even a need for a cast.
And, it's more efficient to use the return value.
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