bswap on prescott

[Török Edvin]

Hi,

If I compile a program using ntohl with '-march=prescott -O2', I get 3
ror instr., however if I compile it with '-march=pentium4 -O2', I get
the bswap instr.

Looking at bits/byteswap.h, it seems that prescott is missing from the list:

# if __WORDSIZE == 64 || (defined __i486__ || defined __pentium__             \
                          || defined __pentiumpro__ || defined __pentium4__   \
                          || defined __k8__ || defined __athlon__             \
                          || defined __k6__)
[...]
__asm__ ("bswap %0",...

Is this intended behaviour? Which is faster on prescott: bswap, or the
3 rotations?

Best regards,
Edwin