make check fails if C++ is enabled

[Alexandre Oliva]

The use of $^ causes the script to be passed as an argument to itself.
Oops :-)

Index: ChangeLog
from  Alexandre Oliva  <aoliva@redhat.com>

	* Makefile ($(objpfx)c++-types-check.out): Don't use $^.

Index: Makefile
===================================================================
RCS file: /cvs/glibc/libc/Makefile,v
retrieving revision 1.247
diff -u -p -r1.247 Makefile
--- Makefile 17 Sep 2005 17:15:50 -0000 1.247
+++ Makefile 22 Sep 2005 00:49:22 -0000
@@ -242,7 +242,7 @@ check-data := $(firstword $(wildcard \
 			  scripts/data/c++-types-$M-$(config-os).data)))
 ifneq (,$(check-data))
 $(objpfx)c++-types-check.out: $(check-data) scripts/check-c++-types.sh
-	scripts/check-c++-types.sh $^ $(CXX) $(filter-out -std=gnu99 -Wstrict-prototypes,$(CFLAGS)) $(CPPFLAGS) > $@
+	scripts/check-c++-types.sh $(check-data) $(CXX) $(filter-out -std=gnu99 -Wstrict-prototypes,$(CFLAGS)) $(CPPFLAGS) > $@
 else
 $(objpfx)c++-types-check.out:
 	@echo 'WARNING C++ tests not run; create a c++-types-XXX file'

-- 
Alexandre Oliva         http://www.lsd.ic.unicamp.br/~oliva/
Red Hat Compiler Engineer   aoliva@{redhat.com, gcc.gnu.org}
Free Software Evangelist  oliva@{lsd.ic.unicamp.br, gnu.org}