Should nanl(0) crash?
Andreas Schwab
schwab@suse.de
Sun Jul 25 04:27:00 GMT 2004
Ulrich Drepper <drepper@redhat.com> writes:
> Petter Reinholdtsen wrote:
>> This code compile, run and print 0 on Tru64 Unix. On Linux, it
>> crashes with a segfault. Is it legal to call nanl(0)? I tried
>> checking the C standard, but that didn't make me wiser. :(
>
> Why should this not crash? It's no different from strlen(0) or atof(0).
It is. The description of the nan functions does not require the argument
to be a string. The last time I asked on comp.std.c I could not get a
definitive answer, but I believe the standard has a defect and nan(0) is
indeed supposed to be undefined.
http://groups.google.de/groups?hl=de&lr=&ie=UTF-8&th=fa4775574d2b6508&seekm=OuqRoZVr2jT%24Ewun%40romana.davros.org&frame=off
Andreas.
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Andreas Schwab, SuSE Labs, schwab@suse.de
SuSE Linux AG, Maxfeldstraße 5, 90409 Nürnberg, Germany
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