acosh patch

Ulrich Drepper drepper@redhat.com
Sat Jul 7 15:49:00 GMT 2001


Stephen L Moshier <moshier@mediaone.net> writes:

> For large x, acosh(x) = log(x) + log(2).  The threshold of "large" is
> 2^28, copied from the double precision routine into the long double
> routines.  That is somewhat too small for 80-bit long double and
> much too small for the 128-bit format.

Thanks, I've applied the patch now.

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