bug in covariance_source.cpp??
Juan Jose Gomez Cadenas
gomez@ific.uv.es
Thu Apr 10 09:54:00 GMT 2003
In covariance_source.cpp, the function:
double
FUNCTION(gsl_stats,covariance) (const BASE data1[], const size_t stride1,
const BASE data2[], const size_t stride2,
const size_t n)
{
const double mean1 = FUNCTION(gsl_stats,mean) (data1, stride1, n);
const double mean2 = FUNCTION(gsl_stats,mean) (data2, stride2, n);
return FUNCTION(gsl_stats,covariance_m)(data1, stride1,
data2, stride2,
n,
mean1, mean2);
}
calls the function covariance_m:
double
FUNCTION(gsl_stats,covariance_m) (const BASE data1[], const size_t
stride1,
const BASE data2[], const size_t
stride2,
const size_t n,
const double mean1, const double mean2)
{
const double covariance = FUNCTION(compute,covariance) (data1, stride1,
data2, stride2,
n,
mean1, mean2);
return covariance * ((double)n / (double)(n - 1));
}
but I believe it should call the function covariance:
static double
FUNCTION(compute,covariance) (const BASE data1[], const size_t stride1,
const BASE data2[], const size_t stride2,
const size_t n,
const double mean1, const double mean2)
{
/* takes a dataset and finds the covariance */
long double covariance = 0 ;
size_t i;
/* find the sum of the squares */
for (i = 0; i < n; i++)
{
const long double delta1 = (data1[i * stride1] - mean1);
const long double delta2 = (data2[i * stride2] - mean2);
covariance += (delta1 * delta2 - covariance) / (i + 1);
}
return covariance ;
}
Regards, JJ
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