[EXTERNAL] Re: Confused by watchpoints on remote protocol

[Denio, Mike]

ram_table was just a symbol I created in assembly.

Its really odd, and its not the symbol itself. For example:

(gdb) watch (uint32_t)ram_table
Watchpoint 1: (uint32_t)ram_table
(gdb) watch *(uint32_t *)&ram_table
Hardware watchpoint 2: *(uint32_t *)&ram_table
(gdb) i b
Num     Type           Disp Enb Address    What
1       watchpoint     keep y              (uint32_t)ram_table
2       hw watchpoint  keep y              *(uint32_t *)&ram_table

I can see both of these variants "watching" the exact same address.

Maybe you are onto something however. I'll try it with a compiled C program and see if the behavior is any different.

Thanks,
Mike

-----Original Message-----
From: Andreas Schwab <schwab@linux-m68k.org> 
Sent: Sunday, August 07, 2022 2:24 AM
To: Denio, Mike via Gdb <gdb@sourceware.org>
Cc: Denio, Mike <miked@ti.com>
Subject: [EXTERNAL] Re: Confused by watchpoints on remote protocol

On Aug 07 2022, Denio, Mike via Gdb wrote:

> The only question I have is that when I type:
> "watch *(uint32_t *)(0x80000018)"
> I get a hardware watch point.
>
> And when I type:
> "watch (uint32_t)ram_table"
> I get a software watch point.

What is ram_table?

> Anyone know why? And how to change it to be always hardware?

Try looking at breakpoint.c:can_use_hardware_watchpoint.

-- 
Andreas Schwab, schwab@linux-m68k.org
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