Viewing the address of an array in gdb
Pedro Alves
palves@redhat.com
Fri Jul 6 12:06:00 GMT 2018
On 07/06/2018 01:00 PM, Pedro Alves wrote:
> On 07/06/2018 12:51 PM, Pedro Alves wrote:
>> On 07/06/2018 04:33 AM, Mahmood Naderan via gdb wrote:
>>> Hi,
>>> I have define "char buffer[100]" in a C code. Trying to view the location of buffer in GDB, I see this
>
> Ah, I missed the "you have defined a buffer yourself" part.
>
> So what seems to be happening is that there's another symbol also
> called "buffer" in glibc:
>
> (gdb) info symbol buffer
> buffer in section .bss of /lib64/libc.so.6
>
> and gdb is picking that symbol instead of yours.
>
> I can reproduce this if I compile a small program without debug info,
> but with debug info (-g), it works as you'd expect.
>
> I don't think we have syntax to disambiguate this, like
> 'libc.so.6'::buffer' vs 'program'::buffer, or program#buffer some
> such, unfortunately.
If you can't change the program, you can work around this by
unloading the shared library symbols, so that gdb sees the
program's symbol again. E.g.:
(gdb) start
Temporary breakpoint 1 at 0x40048b
Starting program: /home/pedro/tmp/buffer
Temporary breakpoint 1, 0x000000000040048b in main ()
(gdb) info symbol &buffer
buffer in section .bss of /lib64/libc.so.6
(gdb) nosharedlibrary
(gdb) info symbol &buffer
buffer in section .bss
(gdb) x /30x &buffer
0x601040 <buffer>: 0x00000000 0x00000000 0x00000000 0x00000000
0x601050 <buffer+16>: 0x00000000 0x00000000 0x00000000 0x00000000
0x601060 <buffer+32>: 0x00000000 0x00000000 0x00000000 0x00000000
0x601070 <buffer+48>: 0x00000000 0x00000000 0x00000000 0x00000000
0x601080 <buffer+64>: 0x00000000 0x00000000 0x00000000 0x00000000
0x601090 <buffer+80>: 0x00000000 0x00000000 0x00000000 0x00000000
0x6010a0 <buffer+96>: 0x00000000 0x00000000 0x00000000 0x00000000
0x6010b0: 0x00000000 0x00000000
(gdb)
Thanks,
Pedro Alves
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