sizeof evaluates expression to compute size?
Senthil Kumar Selvaraj
senthil_kumar.selvaraj@atmel.com
Wed Sep 16 14:41:00 GMT 2015
Hi,
Is it true that gdb evaluates the expression in a "print sizeof(expression)"
to figure out the size?
For one expression on the ARM target
print sizeof((char*)(s->m)
where s is a struct and m is a fixed length char array member)), gdb even
tries to allocate memory in the inferior (through an injected malloc call) to
compute the size.
Am I missing something? Is there a reason why gdb does this? Surely it
should be able to compute the type (and hence the size) statically?
Regards
Senthil
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