printing array in function

Nicolas Sabouret Nicolas.Sabouret@lip6.fr
Fri Sep 3 09:38:00 GMT 2010


Dear Jan,

Le 03/09/2010 11:15, Jan Kratochvil a écrit :
> On Fri, 03 Sep 2010 11:06:02 +0200, Nicolas Sabouret wrote:
>> 1:  void f(int tab[]) {
>> 2:    tab[0] = 1;
>> 3:  }
>> (gdb) p tab     -> (int *) 0xbffff440
> 
> I have only an idea by C++:
> 
> void f(int (&tab)[2]) {
> (gdb) p tab
> $1 = (int (&)[2]) @0x7fffffffde50: {-1, -1}

Thanks for the quick answer. However, your solution requires :
1) to fix the array size in the function signature (this is something we
would prefer to avoid but why not)
2) to use a non-regular syntax in the function signature, which is
someting we cannot do (we want our students to lear the proper C-syntax).

Any other idea ?

-- 
Nicolas Sabouret
LIP6, BC169, 4 place Jussieu, 75005 Paris
http://www-poleia.lip6.fr/~sabouret



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