evaluate more complex expressions using gdb
Bram Kuijper
a.l.w.kuijper@rug.nl
Wed Jun 27 10:20:00 GMT 2007
Hi all,
again a newbie question: can I also evaluate the result of subtractions,
additions using the display command? Like some pointer arithmetics:
display pointer1 - start_pointer
If I do this, gdb gives me the following error:
Disabling display 6 to avoid infinite recursion.
6: pointer1 - start_pointer = One of the arguments you tried to pass to
operator- could not be converted to what the function wants.
Is there any way to to this using gdb?
thanks,
Bram
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