Cann't print local vars when nesting functions
tj
999alfred@comcast.net
Sat Feb 19 19:03:00 GMT 2005
Eli Zaretskii wrote:
>>Date: Fri, 18 Feb 2005 17:54:17 -0500
>>From: Jeff <wd4nmq@comcast.net>
>>
>>int main(int argc, char *argv[]){
>> int i,j;
>>
>> int inside(void){
>> int k,l;
>> k = 3;
>> l = 4;
>> }
>>
>> i = 0;
>> j = 1;
>>}
>>
>>Now set the break point to the same line, j =1, and this happens:
>>Breakpoint 1, main () at test.c:25
>>25 j = 1;
>>(gdb) p i
>>No symbol "i" in current context.
>>(gdb)
>>
>>What gives? Is there something you need to special when nesting functions?
>>
>>
>
>Please tell the details: what platform is this, what versions of GCC
>and GDB you use, and how (with what command-line options) you compiled
>and linked the program. Also, since the line "j = 1;" is not line 25
>in the source you posted, could it be that the program you actually
>compiled was different?
>
>FWIW, I tried this with GCC 3.3.3, naive compiler command line, and
>GDB 6.3, and couldn't reproduce the problem with the source you
>posted.
>
>
>
I am on linux, 2.4.26 kernel
gcc 3.2.3
gdb 5.3
Source file test.c:
#include <stdio.h>
int main(int argc, char *argv[]){
int i,j;
int inside(void){
int k,l;
k = 1;
l = k;
return 0;
}
i = 0;
j = 1;
}
test$ cc -g -O0 test.c
$ gdb ./a.out
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This GDB was configured as "i386-slackware-linux"...
(gdb) b test.c:16
Breakpoint 1 at 0x8048340: file test.c, line 16.
(gdb) run
Starting program: test/a.out
Breakpoint 1, main () at test.c:16
16 j = 1;
(gdb) p i
No symbol "i" in current context.
(gdb)
As stated, removing the inside() function, breaking on the same source
line and printing causes i's value to be printed. No error message.
tj
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