Use of lval_register?
Andrew Cagney
ac131313@redhat.com
Thu Jun 5 15:50:00 GMT 2003
> lval_reg_frame_relative is a relatively recent addition, I believe,
> added to fix some particular problem with values stored in two places.
> Probably around the HP merge? But that's just a guess.
Ah.
> I think that lval_reg_frame_relative, lval_memory, and lval_register
> should all be combined to an lval_location which takes the frame and a
> description of a location, personally.
These will all need to live in harmony for a wile though.
>> In fact, I'm even wondering if GDB should always be setting it to
>> lval_reg_frame_relative, consider the following:
>>
>> (gdb) b main
>> Breakpoint 1 at 0x1802f84: file gdb.c, line 30.
>> (gdb) run
>> Starting program: gdb
>> Breakpoint 1, main (argc=1, argv=0x7fffe434) at
>> /home/scratch/GDB/src/gdb/gdb.c:30
>> 30 memset (&args, 0, sizeof args);
>> (gdb) n
>> 31 args.argc = argc;
>> (gdb)
>> 32 args.argv = argv;
>> (gdb) print args
>> $1 = {argc = 1, argv = 0x0, use_windows = 0, interpreter_p = 0x0}
>>
>> At this point $1 contains not just args value but also it's location.
>> Modify the target state ...
>>
>> (gdb) n
>> 33 args.use_windows = 0;
>> (gdb) print args
>> $2 = {argc = 1, argv = 0x7fffe434, use_windows = 0, interpreter_p = 0x0}
>> (gdb) print $1
>> $3 = {argc = 1, argv = 0x0, use_windows = 0, interpreter_p = 0x0}
>
>
> Agh! That's not right at all! Although I'm not entirely clear on why
> it moved?
The ``print $1''? That output is correct. GDB saves the value so that
it can be refered back to later without having it change.
> I guess the question is, what _should_ happen if a variable moves?
> e.g. we switch to a different item on its location list.
From the users view point, the variable hasn't moved. Hence the
assignment:
$1.argc = N
should always work. Should that assignment update the cached $1 value
as well, hmm....
Andrew
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