gdb seg violation during print command
David Cogen
cogen@ll.mit.edu
Thu May 4 14:15:00 GMT 2000
> Try adding a line or three to main that do nothing.
Like this?
#include <iostream>
int tteesstt11 (int)
{
cerr << "\n";
return 4;
}
int main ()
{
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
cout << "1\n";
}
I set my break on the first cout in main. When I print tteesstt11(1) I still
get the debugger seg violation.
-- DavidC
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