gdb seg violation during print command
David Cogen
cogen@ll.mit.edu
Thu May 4 11:06:00 GMT 2000
> First off, your code is broken. You claim to return an int, but don't.
> This is what is causing the segfault in gdb.
> It's impossible for us to not believe the compiler when it says "this
> function returns an int". We expect it to return an int.
Sorry, that's not it. I have also tried the following:
#include <iostream>
int tteesstt11 (int)
{
cerr << "\n";
return 4;
}
int main ()
{
}
print tteesstt11(1) from a breakpoint in main() still causes gdb to seg
fault. Indeed, I have tried lots of forms for tteesstt11; they all seg fault.
> In the newer gdb, what'll happen is you'll get no segfault, but a weird number
> returned, which will actually the address of the function, which is
> the last value we have around, i guess.
Have you actually tried this or are you supposing? Where can I get the "newer"
gdb? What version is the "newer" gdb?
-- DavidC
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