[PATCH 2/5] gdb: fix printing of flag enums with multi-bit enumerators
Simon Marchi
simark@simark.ca
Mon Feb 17 17:27:00 GMT 2020
On 2020-02-17 5:56 a.m., Luis Machado wrote:
>> @@ -15526,10 +15527,17 @@ update_enumeration_type_from_children (struct die_info *die,
>> Â Â Â Â Â Â Â unsigned_enum = 0;
>> Â Â Â Â Â Â Â flag_enum = 0;
>> Â Â Â Â Â }
>> -Â Â Â Â Â else if ((mask & value) != 0)
>> -Â Â Â flag_enum = 0;
>> Â Â Â Â Â Â Â else
>> -Â Â Â mask |= value;
>> +Â Â Â {
>> +Â Â Â Â Â int nbits = count_one_bits_ll (value);
>> +
>> +Â Â Â Â Â if (nbits != 0 && nbits && nbits != 1)
>
> Isn't this the same as nbits >= 2? popcount shouldn't return a negative number, should it?
I think I wrote that because count_one_bits_ll returns a signed int, so I
indeed thought "what if it returns a negative number". But if it did, there
would be some quite more serious problems, so we probably don't have to think
about it here. I'll change it as "nbits >= 2".
Oh and there was a spurious "&& nbits" in there.
>
>> +Â Â Â Â Â Â Â flag_enum = 0;
>> +Â Â Â Â Â else if ((mask & value) != 0)
>> +Â Â Â Â Â Â Â flag_enum = 0;
>> +Â Â Â Â Â else
>> +Â Â Â Â Â Â Â mask |= value;
>> +Â Â Â }
>> Â Â Â Â Â Â Â Â /* If we already know that the enum type is neither unsigned, nor
>>       a flag type, no need to look at the rest of the enumerates. */
>> diff --git a/gdb/testsuite/gdb.base/printcmds.c b/gdb/testsuite/gdb.base/printcmds.c
>> index 57e04e6c01f3..f0b4fa4b86b1 100644
>> --- a/gdb/testsuite/gdb.base/printcmds.c
>> +++ b/gdb/testsuite/gdb.base/printcmds.c
>> @@ -96,9 +96,35 @@ enum some_volatile_enum { enumvolval1, enumvolval2 };
>>     name. See PR11827. */
>> Â volatile enum some_volatile_enum some_volatile_enum = enumvolval1;
>> Â -enum flag_enum { ONE = 1, TWO = 2 };
>> +/* An enum considered as a "flag enum". */
>> +enum flag_enum
>> +{
>> +Â FE_NONE = 0x00,
>> +Â FE_ONEÂ = 0x01,
>> +Â FE_TWOÂ = 0x02,
>> +};
>> +
>> +enum flag_enum three = FE_ONE | FE_TWO;
>> +
>> +/* Another enum considered as a "flag enum", but with enumerator with value
>> +  0. */
>> +enum flag_enum_without_zero
>> +{
>> +Â FEWZ_ONE = 0x01,
>> +Â FEWZ_TWO = 0x02,
>> +};
>> +
>
> Typo maybe? There is no enum with value 0 in flag_enum_without_zero. Maybe you meant flag_enum to contain a 0 value with FE_NONE?
>
>> +enum flag_enum_without_zero flag_enum_without_zero = 0;
>> +
>
> Or maybe you were referring to the above?
Do you mean a typo in the comment, or the type name? Because there indeed seems
to be a typo, it should read "but with no enumerator with value", not
"but with enumerator with value".
The type name "flag_enum_without_zero" means there is no enumerator that has value
zero, is that clear?
> Otherwise LGTM.
Thanks for your review, I'll likely send a new version.
Simon
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