PATCH: Fix read_leb128 in readelf for 64bit host

Dave Korn dave.korn@artimi.com
Tue Dec 28 14:57:00 GMT 2004


> -----Original Message-----
> From: binutils-owner On Behalf Of H. J. Lu
> Sent: 27 December 2004 19:02

> On Sat, Dec 25, 2004 at 04:42:29PM -0800, H. J. Lu wrote:
> > read_leb128 in readelf assumes long == int == 32bit. It doesn't work
> > with 64bit host. Does this patch look right?
> > 
> > 
> 
> I am going to check in this patch. Gdb 6.3 has the same problem. I
> am enclosing a patch here.

> --- binutils/readelf.c.leb	2004-12-10 14:20:22.000000000 -0800
> +++ binutils/readelf.c	2004-12-27 10:49:33.689234088 -0800
> @@ -6933,7 +6933,7 @@ read_leb128 (unsigned char *data, int *l
>  {
>    unsigned long int result = 0;
>    unsigned int num_read = 0;
> -  int shift = 0;
> +  unsigned int shift = 0;
>    unsigned char byte;
>  
>    do
> @@ -6941,7 +6941,7 @@ read_leb128 (unsigned char *data, int *l
>        byte = *data++;
>        num_read++;
>  
> -      result |= (byte & 0x7f) << shift;
> +      result |= ((unsigned long int) (byte & 0x7f)) << shift;
>  
>        shift += 7;
>  
> @@ -6951,8 +6951,8 @@ read_leb128 (unsigned char *data, int *l
>    if (length_return != NULL)
>      *length_return = num_read;
>  
> -  if (sign && (shift < 32) && (byte & 0x40))
> -    result |= -1 << shift;
> +  if (sign && (shift < 8 * sizeof (result)) && (byte & 0x40))
> +    result |= -1L << shift;
>  
>    return result;
>  }
> 

  IIRC the C spec says shift amounts >=32 are undefined behaviour, even in the
presence of larger integer types.  Is shift ever going to be >= 32 for 64 bit
hosts in these functions?  (I suspect it will).  If so, the shift must be
decomposed into two smaller shifts, no?

    cheers, 
      DaveK
-- 
Can't think of a witty .sigline today....



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