[RFC] eval.c (evaluate_subexp_standard) Deal with c++ referenceargs
Keith Seitz
keiths@cygnus.com
Tue Oct 23 11:48:00 GMT 2001
On Tue, 23 Oct 2001, Daniel Berlin wrote:
> >
> Neither args[0], nor argvec[1], will always be the this pointer.
> Try a static class method.
Oops. I forgot about that. I'll see if I can unwind some of this mess...
Keith
>
> > + /* Before calling a c++ function, check that reference types are
> > + passed as reference types and not something else. */
> > + if (argvec[0] != NULL && exp->language_defn->la_language ==
> > language_cplus)
> > + {
> > + struct type **args;
> > + args = TYPE_ARG_TYPES (VALUE_TYPE (argvec[0]));
> > + if (args != NULL)
> > + {
> > + /* args[0] = "this" pointer
> > + args[1] = first arg type
> > + argvec[0] = method
> > + argvec[1] = "this" pointer
> > + argvec[2] = first argument */
> > + for (ix = 1; args[ix] != NULL
> > + && TYPE_CODE (args[ix]) != TYPE_CODE_VOID; ix++)
> > + {
> > + if (TYPE_CODE (args[ix]) == TYPE_CODE_REF
> > + && TYPE_CODE (VALUE_TYPE (argvec[2+ix-1])) != TYPE_CODE_REF)
> > + {
> > + struct value *v = value_addr (argvec[2+ix-1]);
> > + argvec[2+ix-1] =
> > + value_cast (lookup_reference_type (VALUE_TYPE (v)), v);
> > + }
> > + }
> > + }
> > + }
> > +
> > do_call_it:
> >
> > if (noside == EVAL_SKIP)
> >
> >
>
>
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