[gcc] Bug in emutls?
Takashi Yano
takashi.yano@nifty.ne.jp
Sat Nov 8 12:01:56 GMT 2025
Hi everyone,
I encountered a problem with static thread_local in C++ program.
The following simple reproducer does not work as expected if it
runs under cygwin 3.7.0 (Test), while it works under cygwin 3.6.5.
To conclude, this was not a bug in Cygwin 3.7.0.
This is triggered by the commit:
commit ebd92b128f62a0b3c270319487b8486abdfa405b
Author: Takashi Yano <takashi.yano@nifty.ne.jp>
Date: Fri Apr 4 21:22:27 2025 +0900
Cygwin: thread: Use simple array instead of List<pthread_key>
where the call order of the destructors for pthread_key was changed.
The call order can depend on implementation. So the code using
pthread_key should not expect any predetermined call order of the
destuctors.
The result of the following code is
1: 0xa00016938
2: 0xa00016b98
X::print(): 2
X::print(): 1
X::~X(): 1
X::~X(): 2
under cygwin 3.6.5, while it is
1: 0xa00016938
2: 0xa00016b98
X::print(): 2
X::print(): 1
X::~X(): 2133815816
X::~X(): 2133815816
under cygwin 3.7.0 (Test).
I looked into the problem, and found that the executable for
the following code registers two pthread_keys with each destructor;
one is void emutls_destroy(void *ptr) in libgcc/emutls.c, and the
other is void run(void *p) in libstdc++-v3/libsupc++/atexit_thread.cc.
emutls_destroy() free's the memory erea of static thread_local X,
that is accessed from X::~X() which is called from run(). As a result,
if the emutls_destroy() is called before run(), run() referres to
the memory erea already free'ed.
I think this is a bug of gcc. This issue does not occur in Linux,
because Linux does not use emutls.
Any idea?
#include <thread>
#include <cstdio>
#include <unistd.h>
class X {
int n;
public:
X(int n1) : n(n1) {}
~X() {
printf("X::~X(): %d\n", n);
}
void print() {
printf("X::print(): %d\n", n);
}
};
void func(int n) {
static thread_local X x(n);
printf("%d: %p\n", n, &x);
usleep(10000);
x.print();
usleep(10000);
}
int main() {
std::thread t1(func, 1);
std::thread t2(func, 2);
t1.join();
t2.join();
return 0;
}
Any idea?
--
Takashi Yano <takashi.yano@nifty.ne.jp>
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