[SOLVED] Re: cygwin's [g]make 3.81 seems not to understand conditionals
Thu Jul 19 04:30:00 GMT 2007
Carlo Florendo wrote:
> David Rothenberger wrote:
>> On 7/18/2007 9:03 PM, Carlo Florendo wrote:
>>> I've got (and attached) this simple Makefile that checks the build
>>> platform of a machine.
>>> Here's the cut-and-pasted content of the Makefile:
>>> PLATFORM=$(shell uname -s | cut -f 1 -d " " | cut -f 1 -d "_");
>> Try removing the trailing semicolon. It is not removed by make, so
>> PLATFORM ends up being "CYGWIN;".
> Bingo. That did it!
> So does that mean that make 3.80 was wrong then?
Please ignore this, sorry. Both have the correct behaviour.
When expanded under Linux, the make statements become
ifeq ("Linux;", "CYGWIN)
it will "correctly" output "linux" but it got to the else conditional only
because "Linux;" != "CYGWIN.
The trailing semi-colon confused me. I was treating the Makefile as a bash
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