1.5.9: Trouble with setting variables using 'read' in a script

[Andy Rushton]

Kevan Gelling wrote:

>I'm having trouble setting variables using the 'read' command in bash.
>
>All of the following lines fail to set $var and return a blank line.
>  - echo "text" | read var ; echo $var
>  - cat file | read var ; echo $var
>  - read var < file | echo $var
>  
>
The problem is that the pipeline is executed by spawning a sub-process 
and running a sub-shell in it. The variable that is being read into is 
actually a copy that exists within that sub-shell, not the original that 
you declared in the script. Variables set in sub-shells cannot be passed 
back to their parent shell (the script itself).

>I can get it work by explicitly declaring the file descriptor with the file
>redirection, but I'd prefer to use a pipe.
>  - read -u 0 var <file ; echo $var
>  
>
This doesn't create a sub-shell, so the variable being read is the one 
in the script.

>Another related quirk, is that variables set within 'while read' loops lose
>their values once the loop ends.  The following example displays "text text"
>within the loop and blank line outside.
>  - echo "text" |\
>    while read
>    do 
>      foo=$REPLY ; bar="text"
>      echo $foo $bar
>    done
>    echo $foo $bar
>  
>
The while loop also becomes a sub-shell. Same problem as the pipeline.

This is a 'feature' of bash and indeed all Bourne-shell derivatives. It 
makes a lot of shell features much harder to use than you would expect.

Incidentally, this is why you cannot write shell scripts to change your 
environment. The script runs in a sub-shell, changes the local copy of 
the environment and then discards the local copy on exit leaving the 
parent shell in the same state as it was in before.

Andy

-- 
Andy Rushton, Southampton, UK

We may eventually come to realize that chastity is no more a virtue
than malnutrition.
		-- Alex Comfort


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