cygwin symlink? bug
Randall R Schulz
rrschulz@cris.com
Sun Feb 9 16:06:00 GMT 2003
Max, Trevor,
BASH keeps an internal idea of the current working directory. In the
face of symbolic links, this internal record of the current working
directory may not be identical to that computed by the "pwd" programs
traversal-to-root algorithm.
I use this instead of BASH's built-in pwd command:
wd() {
WD="$(pwd)"
WDP="$(/bin/pwd)"
if [ "$WD" != "$WDP" ]; then
echo "bash: $WD"$'\n'"real: $WDP"
else
echo "$WD"
fi
}
I use this one if I want to see the Windows form of the current working
directory, too:
awd() {
WD="$(pwd)"
WDP="$(/bin/pwd)"
if [ "$WD" != "$WDP" ]; then
echo "bash: $WD"$'\n'"cyg: $WDP"
else
echo "cyg: $WD"
fi
echo "win: $(cygpath -w -a "$(pwd)")"
echo "mix: $(cygpath -m -a "$(pwd)")"
}
Randall Schulz
At 05:48 2003-02-09, Max Bowsher wrote:
>Trevor Forbes wrote:
> > I am having problem with some of my build scripts and the following
> > demonstrates the problem:
> >
> > If run the following (as a script) I get -- /tmp/foo/bar
> > # !/bin/bash
>
>Are you sure? I can reproduce your results only if I change the shebang to
>/bin/sh.
>
> > cd /tmp; mkdir -p foo/bar; ln -f -s foo/bar bar; cd bar; pwd; cd ..
> >
> > If I type the line in a shell then I get what I expected -- /tmp/bar
> >
> > I am using cygwin-1.3.20-1 but do not I think it is a new feature.
> >
> > Is my logic correct?
>
>IIRC, Linux does this too - but I'm not easily able to test that at the
>moment.
>
>
>Max.
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