[PATCH v3] LoongArch: Batch-delete bytes at the end of each relax trip
mengqinggang
mengqinggang@loongson.cn
Mon Jun 16 10:12:34 GMT 2025
在 2025/6/16 下午4:23, WANG Xuerui 写道:
> On 6/16/25 14:52, mengqinggang wrote:
>>
>> 在 2025/6/14 下午10:15, WANG Xuerui 写道:
>>> [snip]
>>>
>>> +static void
>>> +loongarch_relax_perform_deletes (bfd *abfd, asection *sec,
>>> + struct bfd_link_info *link_info)
>>> {
>>> unsigned int i, symcount;
>>> bfd_vma toaddr = sec->size;
>>> @@ -4737,30 +4877,72 @@ loongarch_relax_delete_bytes (bfd *abfd,
>>> Elf_Internal_Shdr *symtab_hdr = &elf_tdata (abfd)->symtab_hdr;
>>> unsigned int sec_shndx = _bfd_elf_section_from_bfd_section
>>> (abfd, sec);
>>> struct bfd_elf_section_data *data = elf_section_data (sec);
>>> - bfd_byte *contents = data->this_hdr.contents;
>>> + bfd_byte *contents = data->this_hdr.contents, *contents_end = NULL;
>>> struct relr_entry *relr = loongarch_elf_section_data (sec)->relr;
>>> struct loongarch_elf_link_hash_table *htab =
>>> loongarch_elf_hash_table (link_info);
>>> struct relr_entry *relr_end = NULL;
>>> + splay_tree pdops = htab->pending_delete_ops;
>>> + splay_tree_node node1 = NULL, node2 = NULL;
>>> if (htab->relr_count)
>>> relr_end = htab->relr + htab->relr_count;
>>> - /* Actually delete the bytes. */
>>> - sec->size -= count;
>>> - memmove (contents + addr, contents + addr + count, toaddr - addr
>>> - count);
>>> + BFD_ASSERT (pdops != NULL);
>>> + node1 = splay_tree_min (pdops);
>>> +
>>> + if (node1 == NULL)
>>> + /* No pending delete ops, nothing to do. */
>>> + return;
>>> +
>>> + /* Actually delete the bytes. For each delete op the pointer
>>> arithmetics
>>> + look like this:
>>> +
>>> + node1->key -\ /- node2->key
>>> + |<-- op1->size -->| |
>>> + v v v
>>> + ...---------------xxxxxxxxxxxxxxxxxxx---------xxxxxxxxxxx----...
>>> + ^
>>> + node1->key + op1->size -/
>>
>> These pointers seem to not change after delete op. The delete op just
>> copy (node1->key+op1->size, node2->key) to node1->key.
>>
> Sorry I didn't understand this, isn't there a "node1 = node2" below in
> the for statement's expression 3 position? But indeed the memmove
> destination is not node1->key as the illustration might suggest
> otherwise, maybe I can clarify that in a v4. What do you think?
I mean the memmove cant change the values of pointers in the
illustration, it just copy a memory.
The illustrations seem to show (node1->key + op1->size) move to
node2->key after delete op.
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