How is .gnu.version resolved?

[Peng Yu]

$ readelf -W -a puts_helloworld.exe
...
Version symbols section '.gnu.version' contains 7 entries:
 Addr: 0x000000000000045a  Offset: 0x00045a  Link: 5 (.dynsym)
  000:   0 (*local*)       0 (*local*)       2 (GLIBC_2.2.5)   2 (GLIBC_2.2.5)
  004:   0 (*local*)       0 (*local*)       2 (GLIBC_2.2.5)
...

I see the .gnu.version above. Which contains 7 numbers 0, 0, 2, 2, 0,
0 and 2. The 2's seems to be the numbers in the numbers in () below.
Is it so? What do these 2's mean?

$ readelf -W --dyn-syms puts_helloworld.exe

Symbol table '.dynsym' contains 7 entries:
   Num:    Value          Size Type    Bind   Vis      Ndx Name
     0: 0000000000000000     0 NOTYPE  LOCAL  DEFAULT  UND
     1: 0000000000000000     0 NOTYPE  WEAK   DEFAULT  UND
_ITM_deregisterTMCloneTable
     2: 0000000000000000     0 FUNC    GLOBAL DEFAULT  UND puts@GLIBC_2.2.5 (2)
     3: 0000000000000000     0 FUNC    GLOBAL DEFAULT  UND
__libc_start_main@GLIBC_2.2.5 (2)
     4: 0000000000000000     0 NOTYPE  WEAK   DEFAULT  UND __gmon_start__
     5: 0000000000000000     0 NOTYPE  WEAK   DEFAULT  UND
_ITM_registerTMCloneTable
     6: 0000000000000000     0 FUNC    WEAK   DEFAULT  UND
__cxa_finalize@GLIBC_2.2.5 (2)

The raw data in .gnu.version is just a bunch of uint16_t if I
understand it correctly. How these numbers are resolved to "*local*"
and GLIBC_2.2.5?

$ readelf -x .gnu.version puts_helloworld.exe

Hex dump of section '.gnu.version':
  0x0000045a 00000000 02000200 00000000 0200     ..............


The input file is generated as below.

$ cat puts_helloworld.c
#include <stdio.h>
int main() {
    puts("Hello World!");
    return 0;
}
$ gcc -o puts_helloworld.exe puts_helloworld.c
$ gcc --version
gcc (Debian 10.2.1-6) 10.2.1 20210110
Copyright (C) 2020 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

-- 
Regards,
Peng