ld -e number makes an entry in symbol table

[Alan Modra]

On Wed, Sep 09, 2009 at 08:50:23AM -0700, H.J. Lu wrote:
> On Wed, Sep 9, 2009 at 8:23 AM, Andreas Schwab<schwab@redhat.com> wrote:
> > This was broken by the patch for PR ld/6766.
> 
> Here is a patch.  OK to install?

I obviously gave the OK for your PR6766 patch too quickly.  I'm
inclined to think the whole patch should be reverted.

Why should -e be any different from ENTRY() in a script?

-- 
Alan Modra
Australia Development Lab, IBM