[xsl] sorted table elements

[Saverio Perugini <sperugin at csgrad dot cs dot vt dot edu>]

Hello,

I'd like to produce a 4 column HTML table where each <td>
element is alphabetically sorted from cell 1,1 to cell n,4
(where n is the required number of rows).

The following is an attempt:

<table>
   <xsl:for-each select="*[position() mod 4 = 1]">
      <xsl:sort data-type="text" select="name()"/>
         <tr>
            <xsl:for-each select=".|following-sibling::node()[position() &lt; 4]">
               <td>...</td>
            </xsl:for-each>
         </tr>
   </xsl:for-each>
</table>

This code only sorts all the *[position() mod 4 = 1] elements.
Therefore, only column one is sorted, whereas I wanted the entire
table (an linear list from cell 1,1 to cell n,4 sorted).  Can this be done?

Thank You and Best Regards,

S. Perugini


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