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RE: Sorting Question: Muenchian method? Substring in Key?
- From: "Robert Koberg" <rob at koberg dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Fri, 27 Sep 2002 09:05:34 -0700
- Subject: RE: [xsl] Sorting Question: Muenchian method? Substring in Key?
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi,
try passing it this way:
<xsl:template match="topics">
<div class="topics">
<xsl:apply-templates select="topics/topic">
<xsl:sort select="."/>
</xsl:apply-templates>
</div>
</xsl:template>
<xsl:template match="topic">
<xsl:variable name="previndex" select="position()-1"/>
<xsl:if test="not(substring(.,1,1) =
substring(/topics/topic[$previndex],1,1))">
<div class="topicTitle"><xsl:value-of select="substring(.,1,1)"/></div>
</xsl:if>
<div class="topic"><xsl:value-of select="."/></div>
</xsl:template>
best,
-Rob
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Thomas_M
> Sent: Friday, September 27, 2002 8:27 AM
> To: 'xsl-list@lists.mulberrytech.com'
> Subject: [xsl] Sorting Question: Muenchian method? Substring in Key?
>
>
> Hello. This is my first XSLT project. I'm having trouble with grouping
> sorted items (seems to be a common theme). I have a XML file like this
> (simplified):
>
> <topics>
> <topic>Anteater</topic>
> <topic>Aardvark</topic>
> <topic>Beetle, Smaller European Elm Bark</topic>
> <topic>Beetle, American Burying</topic>
> <topic>Chimpanzee</topic>
> </topics>
>
> I would like the output to be sorted and grouped, with each group getting a
> heading:
>
> A
> Aardvark
> Anteater
>
> B
> Beetle, American Burying
> Beetle, Smaller European Elm Bark
>
> C
> Chimpanzee
>
> The corresponding part of my XSL is below.
>
> <xsl:template match="topics">
> <table border="1">
> <xsl:for-each select="topic">
> <xsl:sort select="."/>
> <xsl:variable name="previndex" select="position()-1"/>
> <xsl:if test="not(substring(.,1,1)
> = substring(/topics/topic[$previndex],1,1))">
> <tr><th><xsl:value-of select="substring(.,1,1)"/></th></tr>
>
> </xsl:if>
> <tr>
> <td><xsl:value-of select="."/></td>
> </tr>
> </xsl:for-each>
> </table>
> </xsl:template>
>
> As you can see, I'm comparing an element in a sorted node-set with a
> document-order node-set. This works only if the XML is pre-sorted. Is there
> a way to create the sorted node-set first, so that I can both traverse and
> use it in my test?
>
> I have seen a few examples of the Muenchian method, and it would seem this
> is another (perhaps better) way solve my problem. However, I've tried
> several times to implement it and can't seem to get it right (can you use a
> substring in a key?)
>
> Thanks for any insight,
>
> - Mark.
>
> --
> Mark Thomas |_|
> Internet Systems Architect -+-
> User Technology Associates, Inc. |
> Thomas_M@bls.gov /-\
>
>
>
>
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>
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