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Re: Muenchian method on nodes with two or more items for indexing


Thanks J.

This worked great! Just a few corrections for reference on the list (and for my own future purposes :} ). And sorry about not trimming down the content before resending on the previous message.

Thanks again. Saved me from a lot more frustration.

Larry

Corrections to below:

<xsl:for-each select="//LexicalDatabase//index[generate-id(.)=
generate-id(key('entries-by-index',.))]">
^

<xsl:variable name="entry"
select="(ancestor::*[parent::LexicalDatabase])[1]"/>
^


From: "J.Pietschmann" <j3322ptm@yahoo.de>
Reply-To: xsl-list@lists.mulberrytech.com
To: xsl-list@lists.mulberrytech.com
Subject: Re: [xsl] Muenchian method on nodes with two or more items for indexing
Date: Fri, 20 Sep 2002 21:46:11 +0200

larry_hayashi@hotmail.com wrote:
  <xsl:key name="entries-by-index" match="//LexicalDatabase/*"
use=".//index"/>
^^^
Bad idea. I think you actually want to group the "index" elements
by their content:

<xsl:key name="entries-by-index" match="index" use="."/>
<xsl:template match="/">
<xsl:for-each select="//LexicalDatabase//index[generate-id(.)=
generate-id(key('entries-by-index',index))]">
<xsl:sort select="." order="ascending" />
<xsl:variable name="entry"
select="(ancestor[parent::LexicalDatabase])[1]"/>
<IndexItem value="{.}">
<xsl:for-each select="key('entries-by-index', .)">
<entry base="{$entry/base}"/>
</xsl:for-each>
</IndexItem>
</xsl:for-each>
</xsl:template>



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