Re: [xsl] stripping leading and trailing newlines from xml

["Aparna Konduri" <a_konduri at lycos dot com>]

Hello Mike,

Suppose xml is like
-----------------------------------
\n
<xml>
   <tag1>  x </tag>
   <tag2> y </tag> 
</xml>
\n
------------------------------------

where \n is a newline. I want to have the entire format as it is, except for the leading and trailing newlines. I mean the output should be just,

-----------------------------------
<xml>
   <tag1>  x </tag>
   <tag2> y </tag> 
</xml>
------------------------------------

Is there a way in xsl to do this? I tried, normalize-space() only to find out that all the format of xml file is gone. I want to have extra spaces on all the lines, except for the first and last newlines.



Thanks for your help,
Aparna
 

--

On Thu, 8 Aug 2002 14:31:46   
 Mike Brown wrote:
>Aparna Konduri wrote:
>> Is there a way to just strip leading and trailing newlines from 
>> xml using xsl or javascript?
>
>XSLT has somewhat unintuitive rules for how it handles whitespace
>and newlines. You did not provide an example of what you want to
>accomplish, so I guess you meant extraneous whitespace.
>
>An identity transform as discussed in the XSLT spec under "Copying"
>(xsl:copy), with the addition of
>
>  <xsl:strip-space elements="*"/>
>  <xsl:output method="xml" indent="no"/>
>
>is probably what you want.
>
>   - Mike
>____________________________________________________________________________
>  mike j. brown                   |  xml/xslt: http://skew.org/xml/
>  denver/boulder, colorado, usa   |  resume: http://skew.org/~mike/resume/
>
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>


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