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AW: Namespace ?


Oh I forgot the solution:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0"
xmlns:xyz="http://ns.hr-xml.org/RecruitingAndStaffing/SEP-2_0";>
<xsl:template match="/">
<html>
<head>
    <title>
        <xsl:value-of
select="xyz:Resume/xyz:StructuredXMLResume/xyz:ContactInfo/xyz:PersonName/xy
z:FormattedName"
/>
    </title>
</head>
<body>
</body>
</html>
</xsl:template>
</xsl:stylesheet>

Costantino

-----Ursprüngliche Nachricht-----
Von: Sertorio Costantino EVK 
Gesendet am: Donnerstag, 25. Juli 2002 14:39
An: 'xsl-list@lists.mulberrytech.com'
Betreff: AW: [xsl] Namespace ?

That's because your XML has a default namespace. 
You have to change a few things in your stylesheet to select elements in a
default namespace.
You can find the answer to your problem here:
http://www.topxml.com/people/bosley/defaultns.asp

Costantino

-----Ursprüngliche Nachricht-----
Von: stephane [mailto:sbirot@e-manation.com]
Gesendet am: Donnerstag, 25. Juli 2002 14:28
An: xsl-list@lists.mulberrytech.com
Betreff: [xsl] Namespace ?

I want to extract the FormattedName from the following XML file:

<?xml version="1.0" encoding="UTF-8"?>
<Resume xmlns="http://ns.hr-xml.org/RecruitingAndStaffing/SEP-2_0";>
	<StructuredXMLResume>
		<ContactInfo>
			<PersonName>
				<FormattedName>John Doe</FormattedName>
			</PersonName>
		</ContactInfo>
	</StructuredXMLResume>
</Resume>

I use the following XSL file:

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:template match="/">
<html>
<head>
    <title>
        <xsl:value-of
select="Resume/StructuredXMLResume/ContactInfo/PersonName/FormattedName"
/>
    </title>
</head>
<body>
</body>
</html>
</xsl:template>
</xsl:stylesheet>

But this does not work.
In the XML file if I replace
<Resume xmlns="http://ns.hr-xml.org/RecruitingAndStaffing/SEP-2_0";>
By
<Resume>
This work fine

Could anybody explain me why ?

---
Stéphane



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