Re: [xsl] The longest node in a node set

[Antonio Fiol Bonnín <fiol at w3ping dot com>]

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Thank you Dave, Mike and Jeni!

Dave, I was actually thinking of getting the length, not the node. So
both Jeni's and Mike's approaches could work.

However, I have just discovered that I need something far more complex. :-(

The idea was obtaining the max length for all the "column" elements that
may go in a table cell, and then use that number as the argument to
proportional-column-width in XSL-FO. That way I would get a table with
proportional space depending on the max size of the content. Nice idea,
but...

I did not take into account the fact that longer contents are splitted
into two rows at spaces. That changes the formula: I would have to find
"the length of the longest word contained in an element". That would not
change a lot Jeni's recursive approach, except that it would have to be
douoble-recursive to find the length of the words. But never mind. This
is certainly not the best solution, as I have a very irregular
distribution of maximum "word" lengths. So the final result would not be
appealing.

I think I would better go for a hypenation approach. Not that I want
real English words hyphenated, but the idea is as follows:

I have long things like:

0123456-987654-784112-AS-666

This could probably be split as:

0123456-987654-784112-
AS-666

Is there a way to tell the FO renderer that it can cut a word at a
specific place? Some sort of zero length space that must be interpreted
by the FO renderer as exactly that, a space (in the sense of something
that is between words), but 0 length (i.e. Do not draw it if the word is
not splitted).

Or does anyone see a better approach?


Thank you very very much!!


Antonio
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