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Re: XSL -XML to XSL reorienting node
- From: Mike Ferrando <mikeferrando at yahoo dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Thu, 27 Jun 2002 10:38:09 -0700 (PDT)
- Subject: Re: [xsl] XSL -XML to XSL reorienting node
- Reply-to: xsl-list at lists dot mulberrytech dot com
--- David Carlisle <davidc@nag.co.uk> wrote:
> <xsl:if test="child::*">
> <xsl:choose>
> <xsl:when test="name()=''">
>
> That when can never be true.
> If the outer if is true then the current node has child nodes so it
> must be an element node. Element nodes never have an empty name.
I put this in because I was getting empty attributes (and it did get
rid of them but obviously masked another problem).
> in your second one
>
> <xsl:if test="child::*()[not(SCRGRP | SCRGRPX | NON-SCORE |
> that's a syntax error you can't have () anywhere in Xpath 1.
I would have gotten an error message on this one when I tried to
transform it. (DUH!) So it must be a typo on my part. How about
without the ()?
> I didn't understand your problem description so can't give advice
> on what it should be, also I have a plane to catch (literally)
Thanks for your time and have a good trip.
Mike F.
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