Re: [xsl] linkdiff template

[Joerg Heinicke <joerg dot heinicke at gmx dot de>]

Hello Guy,

I can't see an error in your code, maybe somebody else? Did you exactly 
use the code below? Line 12 is the key() - no error with parantheses, 
commas or apostrophes?

What it does:
<xsl:key/> creates one index for each input XML. With key() you can 
easily access these indexed elements, here your <a/>s.
With <xsl:for-each select="document($previous)"> you do not work through 
the whole tree, you only switch the context to the other file, because 
you want to have the indexed <a/>s from there and not from your current 
file. With "document($previous)" you only access the root node '/', so 
there is only one iteration. For multiple iterations you can write 
"document($previous)//a", but as you said it, it's completely useless 
when using keys.

Regards,

Joerg



Guy McArthur wrote:

> I thought I understood, but I get an "unknown error in XPath" on line 12.
> Here is the xsl I'm using: (also tried putting wrapping the key() method 
> with a boolean() method.
> --
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>
>  <xsl:param name="previous"/>
>
>  <xsl:key name="links" match="a" use="@href"/>
>
>  <xsl:output method="text"/>
>
>  <xsl:template match="a">
>   <xsl:variable name="href" select="@href"/>
>   <xsl:for-each select="document($previous)">
>    <xsl:if test="not(key('links', $href))">
>      <xsl:value-of select="$href"/>
>    </xsl:if>
>   </xsl:for-each>
>  </xsl:template>
>
> </xsl:stylesheet>
> --
>
> Also, it would seem by looking at it, that it would walk through all the 
> elements of document($previous) for every matching "a" element. Shouldn't 
> building a key eleminate the need to walk through the tree each time?
>
> Guy

XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list