Re: [xsl] Can you pass a parameter from a stylesheet to the resultingHTML file?

[Joerg Heinicke <joerg dot heinicke at gmx dot de>]

Hello Kathryn,

add these templates to the stylesheets:

> <?xml version="1.0" encoding="UTF-8"?>
>
> <xsl:stylesheet
>     xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>     xmlns:xhtml="http://www.w3.org/1999/xhtml";
>     version="1.0">
>
> <xsl:output method="xml" encoding="UTF-8"/>
>
> <xsl:template match="node() | @*">
> 	<xsl:copy>
> 		<xsl:apply-templates select="node() | @*"/>
> 	</xsl:copy>
> </xsl:template>
<xsl:template match="xhtml:ol[@start='var']">
	<xsl:copy>
		<xsl:apply-templates select="@*"/>
		<xsl:attribute name="start">
			<xsl:value-of select="count(preceding::xhtml:ol/xhtml:li) + 1"/>
		</xsl:attribute>
		<xsl:apply-templates select="node()"/>
	</xsl:copy>
</xsl:template>

> </xsl:stylesheet>
>
>
> The second xsl file filters out any <li> item with a class of "mgronly":
>
> <?xml version="1.0" encoding="UTF-8"?>
>
> <xsl:stylesheet
>     xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>     xmlns:xhtml="http://www.w3.org/1999/xhtml";
>     version="1.0">
>
> <xsl:output method="xml" encoding="UTF-8"/>
>
> <xsl:template match="node() | @*">
> 	<xsl:copy>
> 		<xsl:apply-templates select="node() | @*"/>
> 	</xsl:copy>
> </xsl:template>
<xsl:template match="xhtml:ol[@start='var']">
	<xsl:copy>
		<xsl:apply-templates select="@*"/>
		<xsl:attribute name="start">
			<xsl:value-of 
select="count(preceding::xhtml:ol/xhtml:li[not(@class='mgronly')]) + 1"/>
		</xsl:attribute>
		<xsl:apply-templates select="node()"/>
	</xsl:copy>
</xsl:template>


> <xsl:template match="xhtml:li[@class='mgronly']"/>
>
> </xsl:stylesheet>
>
> Here's what I'm trying to do:  In the first transformation, I need to
> replace "var" in the second <ol> tag with "4".
> In the second transformation, because one of the preceding <li> items is
> filtered out, I need to replace "var" with "3".  (I don't need to have the
> XSL files count the <li> items to compute the "4" and "3", unless it's very
> easy.  I can just hard code "4" and "3".) Is there a way to do this?
>
> Thanks again for all your help--
>
> Kathryn
Regards,

Joerg


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