Re: : RE: [xsl] suppressing default template rules

[Aseef Jamaluddin <j_aseef at yahoo dot com>]

That was very good explanation. I am still working on
the fundementals. Just to check the oder in which the
nodes are processed i made the following changes to my
xml,xsl documents. 

<?xml version="1.0" ?>
<custdet>custdettag
	<employee>emptag</employee>
	<firstname>first</firstname>
	<lastname>last</lastname>
</custdet>

<?xml version="1.0"?> 
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:template match="/">root
<xsl:apply-templates/></xsl:template>

<xsl:template match="*">
	<br/>
	------
	<xsl:value-of select="generate-id()" />
	<xsl:value-of select="name()" />
	------
	<br/>
	<xsl:apply-templates/>
</xsl:template>

<xsl:template match="text()">
	<br/>
	---text---
	<xsl:value-of select="generate-id()" />
	<xsl:value-of select="name()" />
	------
	<xsl:value-of select="."/>
	---/text---
	<br/>
</xsl:template>

</xsl:stylesheet>


The expected output (as per the following node
structure)_

/ (root node)
 +- custdet
 |   +- 'custdettag'
    +- employee
    |   +- 'emptag'
    +- firstname
    |   +- 'first'
    +- lastname
        +- 'last'
was,

root 
------ N400001custdet ------ 
---text--- N400002 ------ custdettag ---/text--- 
------ N400003employee ------ 
---text--- N400004 ------ emptag ---/text--- 
------ N400005firstname ------ 
---text--- N400006 ------ first ---/text--- 
------ N400007lastname ------ 
---text--- N400008 ------ last ---/text--- 

But what i am getting now is

root 
------ N400001custdet ------ 
---text--- N400002 ------ custdettag ---/text--- 
------ N400003employee ------ 
---text--- N400004 ------ emptag ---/text--- 
---text--- N400005 ------ ---/text--- 
------ N400006firstname ------ 
---text--- N400007 ------ first ---/text--- 
---text--- N400008 ------ ---/text--- 
------ N400009lastname ------ 
---text--- N40000A ------ last ---/text--- 
---text--- N40000B ------ ---/text--- 

if i apply <xsl:strip-space elements="*"/> i am
getting the expected output.

from which node does the ---text--- N400005 ------
---/text--- ,---text--- N400008 ------ ---/text---
,etc.. getting printed.

Thanks in advance
Aseef.J


--- Jeni Tennison <jeni@jenitennison.com> wrote:
> Hi Aseef,
> 
> > This could very much be elementary (sorry), but i
> really didnt
> > follow in which order the nodes got processed and
> why i got the
> > contents of firstname and lastname elements
> printed twice before
> > adding the template rule for custdet element. Can
> anyone give some
> > tip as to what really happened with the two cases.
> 
> Your XML structure was:
> 
> <custdet>
>   <employee />
>   <firstname>first</firstname>
>   <lastname>last</lastname>
> </custdet>
> 
> Which translates to a tree that looks like:
> 
>  / (root node)
>  +- custdet
>     +- employee
>     +- firstname
>     |   +- 'first'
>     +- lastname
>         +- 'last'
> 
> When the processor starts processing, it starts at
> the root node and
> tries to find a template that matches it. If it
> doesn't find one, it
> uses the built-in template:
> 
> <xsl:template match="/">
>   <xsl:apply-templates />
> </xsl:template>
> 
> which applies templates to the root node's child
> nodes -- in this case
> the custdet element. Again, if there's no template
> for an element (as
> there isn't for the custdet element), the processor
> uses the built-in
> template:
> 
> <xsl:template match="*">
>   <xsl:apply-templates />
> </xsl:template>
> 
> This applies templates to all the children of the
> element: the
> employee element, the firstname element and the
> lastname element. So
> you get templates applied once to the firstname and
> lastname elements
> because of the built-in template for the custdet
> element.
> 
> When the processor applies templates to the employee
> element, it finds
> the following template:
> 
> <xsl:template match="employee">
>   <xsl:apply-templates select="//firstname"/>
>   <xsl:apply-templates select="//lastname"/>
> </xsl:template>
> 
> Inside the template, you have two
> xsl:apply-templates instructions,
> which apply templates to all the firstname and
> lastname elements in
> the document. So templates get applied to the
> firstname and lastname
> elements for a second time, from within this
> template.
> 
> If you want to only process the firstname and
> lastname elements once,
> then you can either add a template for the custdet
> element that only
> processes the employee element:
> 
> <xsl:template match="custdet">
>   <xsl:apply-templates select="employee" />
> </xsl:template>
> 
> Or you can change the template for the employee
> element so that it
> doesn't apply templates for the firstname or
> lastname elements (or
> remove that template entirely).
> 
> But as Jarno said, if the firstname and lastname are
> information about
> the employee, it probably makes more sense to alter
> your XML
> structure, so that the firstname and lastname
> elements are nested
> inside the employee:
> 
> <custdet>
>   <employee>
>     <firstname>first</firstname>
>     <lastname>last</lastname>
>   </employee>
> </custdet>
> 
> You should then change your template for the
> employee element so that
> the paths are relative to the employee element
> you're on rather than
> getting all the firstname and lastname elements in
> the document:
> 
> <xsl:template match="employee">
>   <xsl:apply-templates select="firstname" />
>   <xsl:apply-templates select="lastname" />
> </xsl:template>
> 
> Cheers,
> 
> Jeni
> 
> ---
> Jeni Tennison
> http://www.jenitennison.com/
> 
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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