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Re: Replace newline characters(\n) with <br>
- From: "Joerg Heinicke" <joerg dot heinicke at gmx dot de>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Thu, 21 Mar 2002 01:24:00 +0100
- Subject: Re: [xsl] Replace newline characters(\n) with <br>
- References: <E2355928804ED21187B500805F571F500F9B0F14@g4ntex1.etrade.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
You can search the archives for 'replace' or 'recursive templates', such
questions are quite often.
<xsl:template match="message">
<xsl:call-template name="replace">
<xsl:with-param name="string" select="."/>
</xsl:call-template>
</xsl:template>
<xsl:template name="replace">
<xsl:param name="string"/>
<xsl:choose>
<xsl:when test="contains($string,' ')">
<xsl:value-of select="substring-before($string,' ')"/>
<br/>
<xsl:call-template name="replace">
<xsl:with-param name="string"
select="substring-after($string,' ')"/>
</xsl.call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Regards,
Joerg
> Hello,
>
> I have the a simple Xml document as shown below
>
> <xml version="1.0">
> <message>
> string1
> string2
> string3
> </Message>
>
> Technically, the strings are separated by newlines. Now when i write an
XSL
> for this document, i want to replace all the newlines with <br> so that
> these strings appear in three lines in the output.
>
> Thanks,
>
>
> Arun Ramadoss
> Professional
> Software Engineer II
> E*TRADE Financial
> w 650-331-6307
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