Re: [xsl] how to increment a variable in a for-each loop

[Wendell Piez <wapiez at mulberrytech dot com>]

Yan,

Your xsl:for-each is throwing you off. It's just selecting the current 
node; but since it is, position() is always 1.

Try it without. If position() is still getting thrown off (which could be 
happening if you are processing nodes you haven't accounted for -- for 
example, whitespace-only text nodes in your source which you can only see 
if you know how to look for them), then try using, instead,

count(preceding-sibling::*)

which is more robust than position() for these purposes; or alternatively 
make sure the apply-templates that is getting you this template is 
constructed to select just the nodes you want (probably the best solution).

If this is unclear, we can explain it better if we see both some source 
data, and the template(s) one step "above" this template (i.e. where 
elements are selected to which this template matches -- i.e. the one that 
says mode="diff_cols"). Concrete examples make discussion easier. :-)

Good luck,
Wendell

At 06:14 PM 1/23/02, you wrote:
>I have a code snippet as below:
><xsl:template match="*" mode="diff_cols">
><xsl:for-each select=".">
>     <xsl:if test="position() mod 2 = 1">
>         <fo:table-cell  background-color="red">
><fo:block><xsl:value-of select="."/></fo:block>
>         </fo:table-cell>
>     </xsl:if>
>     <xsl:if test="position() mod 2 = 0">
>         <fo:table-cell  background-color="blue">
>         <fo:block><xsl:value-of
>select="."/></fo:block>
>         </fo:table-cell>
>     </xsl:if>
>     </xsl:for-each>
></xsl:template>
>
>Unfortunately, it did not work.  The background color
>in all columns is red.
>
>Can you help to debug?


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Wendell Piez                            mailto:wapiez@mulberrytech.com
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