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RE: dynamic grouping of tabular data; one or two transformations?
- From: "Chris Bayes" <chris at bayes dot co dot uk>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Sat, 24 Nov 2001 22:57:02 -0000
- Subject: RE: [xsl] dynamic grouping of tabular data; one or two transformations?
- Reply-to: xsl-list at lists dot mulberrytech dot com
Dan,
Instead of returning a string you might want to do something like
<msxsl:script language="javascript" implements-prefix="user">
<![CDATA[
function DoIt(xml,xsl1) {
var xsl2 = new ActiveXObject("MSXML2.DOMDocument");
xml.nextNode().transformNodeToObject(xsl1.nextNode(), xsl2);
var html = new ActiveXObject("MSXML2.DOMDocument");
xml.transformNodeToObject(xsl2, html);
return html.selectSingleNode("/");
}
]]>
</msxsl:script>
still not tested,
so that you can twiddle with your $result variable as a nodeset.
Ciao Chris
XML/XSL Portal
http://www.bayes.co.uk/xml
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com] On Behalf Of
> Dan Diebolt
> Sent: 24 November 2001 22:24
> To: xsl-list@lists.mulberrytech.com
> Cc: chris@Bayes.co.uk
> Subject: RE: [xsl] dynamic grouping of tabular data; one or
> two transformations?
>
>
> Chris, I deninitely prefer the indention of your second solution:
>
> <msxsl:script language="javascript" implements-prefix="user">
> <![CDATA[
> function DoIt(xml,xsl1) {
> var xsl2 = new ActiveXObject("MSXML2.DOMDocument");
> xml.nextNode().transformNodeToObject(xsl1.nextNode(), xsl2);
> html = xml.nextNode().transformNode(xsl2);
> return html;
> }
> ]]>
> </msxsl:script>
>
> This makes sense. I will test it and report any problems.
> Thanks again.
>
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