Re: [xsl] xpath expression needed

[Jörg Heinicke <joerg dot heinicke at gmx dot de>]

Matching on the root-node:

<xsl:template match="root">
    <xsl:apply-templates
select="level1/field1[following-sibling::field2[1]='some']">
</xsl:template>


Joerg


> Hi List,
>
> I have a XML as follows
>
> <level1 name = 'a'>
>      <field1>value1</field1>
>      <field2>some</field2>
>      <field3>value3</field3>
> </level1>
> <level1 name='b'>
>      <field1>value1</field1>
>      <field2>some</field2>
>      <field3>value3</field3>
> </level1>
> <level1 name='c'>
>      <field1>value1</field1>
>      <field2>someother</field2>
>      <field3>value3</field3>
> </level1>
>
> I want to get all the occurrences of "field1" whose first
following-sibling
> "field2" has a value = "some". In this case it should return me 2nodes
> (except the last one, where the value would be "someother")
>
> Hope I am clear.
>
> Thanks,
> Sanjay


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